Q.state the formula of moment of inertia of a uniform solid sphere about an axis passing through its centre or diameter hence derive the expression for corresponding radius of gyration.
irrelevant answer will be deleted(~￣³￣)~(~￣³￣)~
Answers
Answer:
ᴀɴsᴡᴇʀ
The moment of inertia(M.I) of a sphere about its diameter = 2MR²/5
According to the theorem of parallel axes, the moment of inertia of a body about any axis is equal to the sum of the moment of inertia of the body about a parallel axis passing through its centre of mass and the product of its mass and the square of the distance between the two parallel axes.
The M.I. about a tangent of the sphere = 2MR² / 5 + MR² = 7MR² /5
ᴍɪss_ɪɴɴᴏᴄᴇɴᴛ
The moment of inertia (M.I.) of a sphere about its diameter=2MR
2/5
According to the theorem of parallel axes, the moment of inertia of a body about any axis is equal to the sum of the moment of inertia of the body about a parallel axis passing through its centre of mass and the product of its mass and the square of the distance between the two parallel axes.
The M.I. about a tangent of the sphere =2MR