Question

Q.sum of the areas of two squares is 850sq.m. if the difference of their perimeter is 40m, find the sides of the two squares.
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Let the side of first square = x metre

side of second square = y meter

According to question

x^2 +y^2 = 850 Equation(1)

4x - 4y =40

x - y =10 Equation (2)

x = 10 +y

( 10 +y)^2 + y^2 = 850

100 + 20y +y^2 +y^2 =850

2y^2 + 20y -750 = 0

y^2 +10y -375 =0

y^2 + 25y -15y -375 =0

y(y -25) -15(y -25) =0

(y-15)(y -25)=0

y = 15, 25

One square with side 15 m and other with side 25 m