Q. Suppose a light starts travelling through an optical fibre which has refractive index equal to that of the refractive index of water. Eventually the light reaches
the end point of the fibre and exits into air.
(a) If the incidence angle (1) of the light at the end of the fibre is 30°, then what will be the angle of refraction (1) outside the fibre?
(b) What will be the variation if the incident angle is 60°?
(Note: Take sin-2(0.665) = 41°, sin +0.719) = 46°, sin(0.682) = 43°, sin(0.669) = 42°, and sin 60º = 0.866) is
options:
A.42°, 1.345
B. 46°, 1.247
C.43°, 1.456
D.41°, 1.151
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Answer:
The correct answer of this question is the material employed in the lens has the same refractive index as the water surrounding it
Explanation:
Given - A light starts traveling through an optical fiber that has a refractive index equal to that of the refractive index of water. Eventually, the light reaches the end point of the fiber and exits into the air.
To Find - Eventually, the light reaches the end point of the fiber and exits into the air.
The material employed in the lens has the same refractive index as the water surrounding it
At right angles to the surface, the light beam enters and exits the lens. This WI occurs when a light beam passes through the lens's primary axis.
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