q(t) = (t+1)² - (t-1)² find the zeroes of the polynomial
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Answer:
1/9
Step-by-step explanation:
9t2 - 6t + 1 = 0
9t2 - 3t -3t + 1 = 0
3t(3t -1) -1 (3t-1) =0
(3t-1)(3t-1) =0
Both roots are same and = t = 1/3.
Sum of the roots = -b/a = -(-6/9) = 2/3
1/3 + 1/3 = 2/3
Product of roots = (c/a) = 1/9
1/3 x 1/3 = 1/9.
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