Q) Table is given draw the NFA and convert it to DFA
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State 0 1
→q0 {q0, q1} {q1}
*q1 ϕ {q0, q1}
Now we will obtain δ' transition for state q0.
δ'([q0], 0) = {q0, q1}
= [q0, q1] (new state generated)
δ'([q0], 1) = {q1} = [q1]
The δ' transition for state q1 is obtained as:
δ'([q1], 0) = ϕ
δ'([q1], 1) = [q0, q1]
Now we will obtain δ' transition on [q0, q1].
δ'([q0, q1], 0) = δ(q0, 0) ∪ δ(q1, 0)
= {q0, q1} ∪ ϕ
= {q0, q1}
= [q0, q1]
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