Question

Q :
$log_{3}4\: log_{4} 5 \: log_{5}6 \: log_{6}7 \: log_{7}8 \: log_{8}9$
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Answer 1

Answer:

2

Step-by-step explanation:

$log_{3}(4) log_{4}(5) log_{5}(6) log_{6}(7) log_{7}(8) log_{8}(9)$

$= log_{3}(9)$

$= log_{3}( {3}^{2} )$

$= 2 log_{3}(3)$

$= 2 \times 1$

$= 2$

Answer 2

Answer:

2

Step-by-step explanation: