Question

q)The acceleration of a particle which is depends on time is given by following function a = 2t + 1 and at
time t=0, x= 1m and u = 2 m/s. The displacement of the particle at t = 3sec
1) 20.5 m
2)19.5m
3)12m
4)11m​

Answer 1

Answer:

Explanation:

By putting the value in equation a=v-u/t

Answer 2

Answer:

The displacement of the particle at t = 3sec is 11m i.e.option(4).

Explanation:

From the question we have,

$a=2t+1$     (1)

Where,

a=acceleration of a particle

t=time in seconds

The values given in the question are,

t=0

x=1m

The initial velocity(u)=2m/s

By substituting t=0 in equation (1) we get;

$a=2\times 0+1$

$a=1m/s^2$   (2)

From the second equation of motion we have,

$S=ut+\frac{1}{2}at^2$        (3)

By substituting the required values in equation (3) at "t=3 sec" in equation (3) we get;

$S=2\times 3+\frac{1}{2}\times 1\times (3)^2$

$S=6+4.5$

$S=10.5\approx 11$

Hence, the displacement of the particle at t = 3sec is 11m i.e.option(4).

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