Question

Q: The activation energy of one of the reactions in a biochemical process is 87 kJ mol-1. The change in rate constant when the
temperature falls from 37°C to 15°C is?​

Answer 1

Answer:

k=Ae

−

RT

E

a

So,

k

2

k

1

=e

−

R

E

a

(

t

1

1

−

T

2

1

)

=e

−

R

E

a

(

310

1

−

288

1

)

=13.2