Q. The age of a father and a son together 66 year. The age of the father is the age of the son but with the digits reversed.
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Answers
Answered by
5
The answer is given below :
Now,
66 = 51 + 15 = 42 + 24 = 60 + 06
So, we have a set of ages of the father and the son as follows :
(51, 15), (42, 24) and (60, 06).
Thank you for your question.
Now,
66 = 51 + 15 = 42 + 24 = 60 + 06
So, we have a set of ages of the father and the son as follows :
(51, 15), (42, 24) and (60, 06).
Thank you for your question.
Anonymous:
good:-)
Answered by
6
Let x be the required ten's digit number and y be the required unit's digit num.
Let the Father's age be 10x + y.
Then the son's age will be 10y + x.
Now,
Given that the age of the father and a son together is 66 years.
10x + y + 10y + x = 66
11x + 11y = 66
x + y = 6.
Now,
The possibilities are:
(1) 6 + 0 = 6, 0 + 6 = 6 ---------- (60,06).
(2) 5 + 1 = 6, 1 + 5 = 6 ----------- (51,15)
(3) 4 + 2 = 6, 2 + 4 = 6 ---------- (42,24).
The possible solutions are (60,06), (51,15), (42,24).
Hope this helps!
Let the Father's age be 10x + y.
Then the son's age will be 10y + x.
Now,
Given that the age of the father and a son together is 66 years.
10x + y + 10y + x = 66
11x + 11y = 66
x + y = 6.
Now,
The possibilities are:
(1) 6 + 0 = 6, 0 + 6 = 6 ---------- (60,06).
(2) 5 + 1 = 6, 1 + 5 = 6 ----------- (51,15)
(3) 4 + 2 = 6, 2 + 4 = 6 ---------- (42,24).
The possible solutions are (60,06), (51,15), (42,24).
Hope this helps!
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