Q.) The amount of air present in a cylinder when a vacuum pump removes 1/4 of the air remaining
in the cylinder at a time.
☝️☝️In this situation does the list of numbers involved make an arithmetic progression, and why☝️☝️
Answer:-
No, Volumes are V, (3V/4), (3/4)^2V ,...
Answer should be V, (3V/4), (3/4)^2V ,...
please answer only if you know the correct solution step - by - step
Answers
Answered by
1
Answer:
Hope it helps!! Mark this answer as brainliest if u found it useful and follow me for quick and accurate answers...
Step-by-step explanation:
Refer to image attached...
Attachments:
Answered by
2
Answer:
let
the air present in cylinder be x
the amount of air removed = 1/4*x
=x/4
the amount of air removed next time=1/4*x/4
=x/8
the amount of air removed next time =1/4*x/8
=x/32
therefore,it is not an ap
Similar questions