Question

Q. The angle of depression from
the top of the tower 24 m high
at a point on the ground is 30.
The distance of the point from
the top of the tower is:​​

Answer 1

Answer:

Let BC be x metre and AB be v meter.

In ΔADB.

tan 60

∘

=

AB

BD

3

=

y

20+x

In ΔABC

tan 30

∘

=

AB

BC

3

1

=

y

x

y=x

3

Putting the value of r in equation (1)

3

=

x

3

20+x

3x = 20 + x

2x = 20 ⇒ x = 10 m

Height of the tree 20 + 10 = 30 m.

Distance between point and foot of the tree

=

3

30

=10

3m

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