(q)the area of a rectangle is 4 times the area of a square. the length of the rectangle is 90 cm and the breadth of the rectangle is 2/3 of the side of the square. what is the side of the square ?
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Answered by
9
let 'a ' be the side of the square.
length of the rectangle = 90 cm
beadth of rectangle = ( 2/ 3 ) × a
Find the area of rectangle :
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area of rectangle = length × breadth
= 90 × ( 2/ 3 ) × a = 60a cm^2
area of square = a × a = a^2
Solve for side of square (a) :
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according to the given statement :
area of rectangle is 4 times the area of square
60a = 4 × a^2
4a = 60 => a = 15 cm
Answer : side of the square = 15 cm
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length of the rectangle = 90 cm
beadth of rectangle = ( 2/ 3 ) × a
Find the area of rectangle :
---------------------------------------
area of rectangle = length × breadth
= 90 × ( 2/ 3 ) × a = 60a cm^2
area of square = a × a = a^2
Solve for side of square (a) :
---------------------------------------
according to the given statement :
area of rectangle is 4 times the area of square
60a = 4 × a^2
4a = 60 => a = 15 cm
Answer : side of the square = 15 cm
----------------------------–--------------------------
Answered by
3
HI,here ur answer
AREA or RECTANGLE is =4X^2
let area of SQUARE is =X^2
LET ONe Side of SQUARE be X
So, BREATH Of RECTANGLE is 2/3×X
=2X/3
GIVEN LENGTH of RECTANGLE is 90
AREA of RECTANGLE is LENTG4 ×BREATH
SO,According to questions
90×2x/3=4x^2
30×2x=4x^2
60x=4x^2
60=4x^2/x
60=4×x×x/x
60=4x
x=15
So, the SIDE Of SQUARE is 15Cm
Mark As BRAILIEST ANSWER.
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