Q.The brake applied to a car produce an acceleration of 8m per second square in opposite direction to the motion.If the car takes 5 sec to stop after the application of brake,Calculate the distance it travels during this time
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Acceleration a = -8 m/s^2
Time t = 5 s
Final velocity v = 0 m/s
Let initial velocity be u
Let distance be s
v = u + at
So, 0 = u + (-8)(5)
So, u = 40 m/s
Now, s = ut + (1/2) at^2
So, s = 40(5) + (1/2)(-8)(5^2)
So, s = 200-100
So, s = 100 m
Thus, distance travelled is 100 m
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Q.The brake applied to a car produce an acceleration of 8m per second square in opposite direction to the motion.If the car takes 5 sec to stop after the application of brake,Calculate the distance it travels during this time
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