Question

Q. The common factor of

6a3b4c2, 21a2b and 15a3 is​

Answer 1

Answer:

is 3a square

Step-by-step explanation:

6a^3 b^4 c^2

Factors= 3a^2, 2a, b^4, c^2 (I have taken these to make less steps. U take full no.s only)

21a^2b

Factors= 3a^2, 7b

15a^3

factors= 3a^2, 5a

Common factor reached is 3a^2. So, answer is 3a^2.

Answer 2

Given,

The three terms:

$6 {a}^{3} {b}^{4} {c}^{2}$, 21a²b and 15a³

To find,

The common factor.

Solution,

We can easily solve this problem by following the given steps.

According to the question,

We have the following three terms:

$6 {a}^{3} {b}^{4} {c}^{2}$, 21a²b and 15a³

Now, to find the common factor, we will find the prime factors of the number.

6a³b⁴c² = 2×3×a²×a×b⁴×c²

21a²b = 3×7×a²×b

15a³ = 3×5×a²×a

Now, we find that following are the common factors among the three terms:

3×a²

3a²

Hence, the common factor of $6 {a}^{3} {b}^{4} {c}^{2}$, 21a²b and 15a³ is 3a².