Math, asked by faizan301613, 9 months ago

Q) The cost of a machine depreciated by
₹4000 during first year and by ₹3600
during the second year. Calculate :
i) the rate of depriciation.
ii) the original cost of machine.
iii) it's cost at the end of the third year.
{By using the formula of (P x T x R)/100}.

Answers

Answered by bhainapranitsp3610
1

Answer:

hope this helps u ✔✌

Step-by-step explanation:

1) depreciated money of 1st year-2nd year= 4000-3600=400

R=I×100/P×T

R=400×100/4000×1 =10%

Therefore rate of depreciation =10%

2) depreciated price of the 1st year=4000

P=I×100/R×T

P=4000×100/10×1 =40000

Therefore orignal cost=40000

3) 1st year A=40000-4000= 36000

2nd year A= 36000-3600=32400

For 3rd year I=P×R×T/100

32400×10×1/100 =3240

A= 32400-3240 (because of depreciation)

A= 29160

✌✔

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