Question

Q)The current in the secondary coil of a transformer is 1 A and that in the primary is 0.5 A. a) What type of a transformer is this? b) If 200 V is available in the secondary coil of this transformer, what is the voltage in the primary?​

Answer 1

Answer:

968v is the ans of given question

Answer 2

Answer:

The current in the secondary coil of a transformer is 1A and that is the primary is 0.5 if 200v is available in the secondary coil of the transformer, the voltage of the primary​ coil is 400v and it is a step-down transformer

​Explanation:

• In a transformer, there is a primary coil with a number of turns $N_{1}$ voltage, and current through it is $I_{1}$. In the secondary coil, the number of turns is $N_{2}$ voltage is $V_{2}$ and current is $I_{2}$

• The relation connecting these parameters is given by the formula

        $\frac{N_{1} }{N_{2} } =\frac{V_{1} }{V_{2} }=\frac{I_{2} }{I_{1} }$

From the question, we have

current in the primary coil $I_{1} =0.5A$

current in the secondary coil $I_{2} =1A$

the ratio of currents  $I_{1} /I_{2} =0.5$

the voltage in the secondary coil is $V_{2} =200v$

the voltage in the primary coil $V_{1} =\frac{I_{2} }{I_{1} } V_{2}$

⇒$V_{1} =200/0.5=400v$

Since the primary voltage is more than that of the secondary the given transformer is a step-down transformer