Q.The degree of hardness of a given sample of hard water is 60 ppm. if entire hardness is due to MgSO4 how much of MgSO4 is present per kilogram of hard water??
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Answer:
1 mol MgSO4=1molCaco3
2 mol MgSO4=2molCaco3
i.e 2×100gCaCO3
∴
Hardness of water = 220 ppm
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ℏ✺ℓᾰ ժḙᾰԻ!!
Degree of hardness of water= 60ppm
10^6 g of water contain MgSO4
= 60 × 120 /100
= 72g
10^3 g of water will contain MgSO4
= 72/10^6 × 10^3
= 0.072g
1Kg of water contains MgSO4
= 72mg
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