Question

Q :- The density of ice is 0.921 g cm⁻³. Calculate the mass of a cubic block of ice which is 76 mm on each side.

CORRECT ANSWER :- 4.0 × 10²g.

NEED PROPER STEPS AND EXPLANATIONS TOO ! ( Help me with this ) Anyone?

CLASS : 11th Chemistry CH : 1 ( SOME BASIC CONCEPTS OF CHEMISTRY )

#NO SPAM ANSWERS PLEASE #

Answer 1

HEY MATE!

We are provided with the density of the ice block as 0.921gm/cm^3.

Also we are given that length of each side as 76mm => 7.6cm

Now we take out the volume of the cubic ice brick which is given by => (edge) ^3

=> (7.6×7.6×7.6) cm^3

Now to find out the mass we apply the formula :

$density = \frac{mass}{voume} \\ \\ mass = density \: \times volume \\ \\ mass \: = 0.921 \times 7.6 \times 7.6 \times 7.6 \\ \\ mass = 404.296896 \:</em></strong><strong><em> gm$

Which is approximately equal to

4.0 ×10^2 (or simply say 400 gm).

Hope it helps

$<marquee><strong><em>HAKUNA </em></strong><strong><em>MATATA </em></strong>$

Answer 2

Solution :-

As given :-

Density of ice = 0.921 g /cm³

Length of side of cubic block of ice

= 76 mm

Now as we are known :-

$\star \sf{ Density = \dfrac{Mass}{Volume}}$

✨Volume of cube = (length of side)³

= l³

Now

Volume

= (76 mm)³

or

= (7.6 cm )³

= 438.976 cm³

Now by putting Value of volume in Density :-

$\rightarrow \sf{ Density = \dfrac{Mass}{Volume}}$

$\rightarrow \sf{ 0.921 = \dfrac{Mass}{438.976}}$

$\rightarrow \sf{ Mass = 0.921 \times 438.976 }$

$\rightarrow \sf{ Mass = 404.297 \: g }$

$\rightarrow \sf {Mass = 4.043 \times 10^{2}}$

$\rightarrow \sf {Mass = 4 \times 10^{2} \: g}$

So the Mass of the block of Ice

$\large{\boxed{ \sf {Mass = 4 \times 10^{2}\: g}}}$