Question

Q. The diagonal of a rectangle field is 15 m and its area is 108 m2. What is the cost of fencing the field at ₹50.50 per m?​

Answer 1

Step-by-step explanation:

☘Answer:-

Given:-

• Diagonal rectangle = d = 15m.
• Area of rectangle = A = 108m².
• Cost of fencing = Rs. 50.50/m

To find:-

• The cost of fencing.

✪ Formula used:-

Let sides of a rectangle be length (l) and breadth (b)

• Area of rectangle = l×b
• Diagonal of Rectangle = $\sqrt{l {}^{2} \: + \: b {}^{2} }$
• Perimeter of rectangle 2×(l+b)

Solution:-

$Diagonal \: \: of \: \: Rectangle \: = \: d \: = \: 15$

$= > \: \: \sqrt{l {}^{2} \: + \: b {}^{2} } \: = \: 15$

$= > \: l {}^{2} \: + \: b {}^{2} \: = \: 15 {}^{2}$

$= > \: l {}^{2} \: + \: b {}^{2} \: = \: 225 \: \: \: \: \: \: - - - - - (1)$

$\:$

$Area \: \: of \: \: rectangle \: \: = \: A \: = \: 108$

$= > \: l \times b \: \: = \: 108$

$= > \: 2 \times l \times b \: \: = \: 216 \: \: \: \: \: \: \: \: - - - - (2)$

$Adding \: \: equation \: \: 1 \: \: and \: \: 2$

$\: \:$

$= > \: l {}^{2} \: + \: b {}^{2} \: + \: 2lb \: = 225 \: + \: 216$

$= > \: (l + b) {}^{2} \: = \: 441$

$= > \: l \: + \: b \: = \: 21$

$\:$

$perimeter \: = \: \: 2 \times \: (l \: + \: b)$

$= > \: 2 \times 21 \\ = > \: 42m.$

$\: \:$

$Cost \: \: of \: \: fencing \: \: = Perimeter \: \: × \: \: cost \: \: of \: fencing \: \: per \: \: meter.$

$= > \: 42 \: \times \: 50.50$

$= > \: 2121$

$\: \:$

✿$The \: \: cost \: \: of \: \: fencing \: \: is \: \: Rs. \: \: 2121$

Answer 2

Step-by-step explanation:

Science is the pursuit and application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence. Scientific methodology includes the following: ... Evidence. Experiment and/or observation as benchmarks for testing hypotheses.