Question

Q.The diagonal of a rectangle is 2under root 13cm.If its length and breadth are in the ratio 3:2, then find its area.​
Now i'm not sad ​

Answer 1

Area of rectangle = length × breadth

Answer 2

Here, ABCD is a square

All sides of the square are equal.

Given:-

Let AB=BC=CD=AD=acm

AC=13cm

In right-angled △ABC,

$\implies \: \sf \: (AC {)}^{2} = {(AB})^{2} + (BC {)}^{2}$

$\sf{ \orange{ \bigstar{ \red{ \underline{ \green{ \fbox{by \: Pythagoras \ \: theorem}}}}}}}$

$\sf \implies \: \: (13 {)}^{2} = {a}^{2} + {a}^{2}$

$\longmapsto \sf \: \: ( {13)}^{2} = {2a}^{2}$

$\implies \: \sf \: \: {a}^{2} = \frac{(1 {3)}^{2} }{2}$

$\sf \implies \: \: a = \frac{13}{ \sqrt{2} }$

$\sf{ \purple{ \fbox{ \pink{taking \:square \: root \: both \: sides }}}}$

$\sf \implies \: a = \frac{13 \times \sqrt{2} }{ \sqrt{2} \times \sqrt{2} }$

$\sf{ \orange{ \boxed{ a = \frac{13 \sqrt{2} }{2}}}}$

$\rule{1222pt}{3.0pt}$

${ \bf{ \pmb{ \frak{ \pink{hope \: its \: help \: u \: }}}}}$

$\sf \red{be \: brainly...}$