Question

Q) The diagonals of a rhombus are 10cm and 24 cm. Find its

area.​

Answer 1

Correct Question:-

The diagonals of a rhombus are 10cm and 24 cm. Find its area.

Given:-

• Diagonal (1) = 10 cm
• Diagonal (2) = 24 cm

To Find:-

• Area of Rhombus

Solution:-

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathfrak{ \underline{ \purple{Formula \: to \: calculate \: the \: area \: of \: Rhombus}}}$

$\boxed{\mathfrak{ \green{ \large{ \star \: \: \: \: \: { \red{area = \frac{1}{2} \times diagonal(1) \times diagonal(2)}}}}}}$

According to question,

$\large{ \tt \longmapsto \: \: \: \: \: \: \: \:area = \frac{1}{2} \times 10 \times 24}$

$\large{ \tt \longmapsto \: \: \: \: \: \: \: \:area = 5 \times 24}$

$\large{ \tt \longmapsto \: \: \: \: \: \: \: \:area = \boxed{\green{ \mathfrak{120 \: {cm}^{2} }}}}$

Hence,

• The area of Rhombus is 120 cm²

Answer 2

Answer:

length of base= 10/2=5

length of height=24/2=12

by Pythagoras theorem,

hypotenuse= (5)²+(12)²

(AB)²=25+144

(AB)²=169²=√(13)²

H= 13CM

SO ,the side of rhombus is 13 cm

perimeter of rhoumbus=4*side

=4*13

= 52cm

therefore ,the perimeter of rhombus is 52cm.