Q. The electrons are separated by a distance 'r' meter and have a coulomb force 'F' Now two 'alpha' particles Separated '2r' distance what will be force on them asbcompare to first case?
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Answer:
F/4 is the answer.
Explanation:
according to coulombs law
F=1/ 4πEo x (e)(e)/r²
F1=1/ 4πEo x (e)(e)/r²
Charge on proton is equal to charge on electron and charge on single Ionized by atom separated by distance "2r"
F2=1/ 4πEo x e²/4r²
F1/F2=F/4
answer is F/4
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