Physics, asked by darshanarajkonwar, 9 months ago

Q. The electrons are separated by a distance 'r' meter and have a coulomb force 'F' Now two 'alpha' particles Separated '2r' distance what will be force on them asbcompare to first case?​

Answers

Answered by kamarlailasami
2

Answer:

  1. എനിക്ക് അറിയില്ല plzz
Answered by VaibhavSR
0

Answer:

F/4 is the answer.

Explanation:

according to coulombs law

F=1/ 4πEo x (e)(e)/r²

F1=1/ 4πEo x (e)(e)/r²

Charge on proton is equal to charge on electron and charge on single Ionized by atom separated by distance "2r"

F2=1/ 4πEo x e²/4r²

F1/F2=F/4

answer is F/4

#SPJ3

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