Question

Q.The elevation angle of the top of a 10 m high pole from a point on the ground 10√3 m away from the pole, is...​

Answer 1

Answer:

elevation is $30^{\circ}$

Step-by-step explanation:

$tan(\theta)=\dfrac{10}{10\sqrt{3}}=\dfrac{1}{\sqrt{3}}$

elevation,

$\theta =tan^{-1}(\dfrac{1}{\sqrt{3}})=\pi/6 =30^{\circ}$

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