Question

Q. The equation of a trajectory is giremby
y =√3x-5x^2
fimdir
a Time of Flight
a) Horizontal pange
.) maximum height
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Answer 1

Answer:

solved

Explanation:

x = utcos∝ , t = x/ucos∝

y = utsin∝ - gt²/2 = x tan∝ - gx²sec²∝/2u²

y = x tan∝ - gx²sec²∝/2u² = √3x - 5x²

now comparing coeffecients

tan∝ = √3 , ∝ = 60°

5 = gsec²60/2u² , 10u² = 10sec²60 , u = sec 60 = 2 m/s

Time of Flight  = 2usin60/g = √3/5 sec.

a) Horizontal pange  = 2²sin120°/10 = √3/5 m.

.) maximum height = 2²sin²60°/20 = 0.15 m