Question

Q. The escape velocity from the earth surface is 11.2 km s-1. Calculate the escape velocity from a planet of radius and mass twice that of the earth?​

Answer 1

Answer:

The escape velocity from a planet of radius and mass twice that of the earth will also be 11.2 Km/s.

Explanation:

Escape velocity is the minimum velocity required for an object to escape from the gravitational field of a planet. The value of escape velocity may change from planet to planet. This is because of the change in mass and radius of each planet. The formula of escape velocity is given as follows:

v = √(2GM / r)

If the mass is doubled, the mass in the above equation becomes M = 2M and the radius will change as, r = 2r. We can rewrite the equation as:

v = √(2G2M / 2r)

But the effect will be canceled as the numerical value of 2 is added in both the numerator and denominator of the equation.

So the escape velocity from a planet of radius and mass twice that of the earth will be the same as that of the earth.