Question

Q.the expression √3-1 / 2√2-√3-1 is equal to _____ a) √2+√3+✓4+√6 B)√6-√4+√3+√2 C)√6-√4-√3+√2 D) NOT (NONE OF THESE)

Answer 1

Answer:

$\frac{ \sqrt{3} - 1 }{2 \sqrt{2} - \sqrt{3} - 1} = \frac{ (\sqrt{3} - 1)(2 \sqrt{2} + \sqrt{3} + 1) }{(2 \sqrt{2} - ( \sqrt{3} + 1))(2 \sqrt{2} + \sqrt{3} + 1) } =$

$\frac{2 \sqrt{6} - 2 \sqrt{2} + 3 - 1 }{(2 \sqrt{2} ) {}^{2} - ( \sqrt{3} + 1) {}^{2} } = \frac{2 \sqrt{6} - 2 \sqrt{2} + 2 }{8 - 3 - 1 - 2 \sqrt{3} } =$

$\frac{ \sqrt{6} - \sqrt{2} + 1 }{2 - \sqrt{3} } = \frac{ \sqrt{6} - \sqrt{2} + 1 }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } =$

$\frac{2 \sqrt{6} - 2 \sqrt{2} +2 + \sqrt{18} - \sqrt{6} + \sqrt{3} }{4 - 3} =$

$\sqrt{6} - 2 \sqrt{2} + 2 + 3 \sqrt{2} + \sqrt{3}$

$= \sqrt{6} + \sqrt{3} + \sqrt{2} + 2 = \sqrt{2} + \sqrt{3} + \sqrt{4} + \sqrt{6}$

Option A is correct.

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Answer 2

Answer:

Explanation:

Ok