Question

Q. The Given figure are drawn using more than one triangle. Find :-
(ii) <FAB + <ABC + <BCD + <CDE + <DEF + <EFA .​

Answer 1

Answer:

720°

Step-by-step explanation:

∆AFE+∆AED+∆DAC+∆ABC=180°×4=720°.

angleAEF+angle F+angleFAE in ∆AFE=180°

Amgle EAD + angle ADE + ANGLE DCA IN ∆ EAD = 180°

ANGLE DAC + ANGLE ACD + ANGLE CDA IN ∆ ACD = 180°

ANGLE CAB + ANGLE ABC + ANGLE ACB = 180°

SO, SUM OF ALL ANGLES = 720°

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