Question

Q- The greatest number which divides 134 and 167 leaving 2 as remainder in each case is :_______ please tell with explainiton​

Answer 1

Answer:

190 is ur answere

Step-by-step explanation:

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Answer 2

Answer:

The greatest number which divides 134 and 167 leaving 2 as remainder in each case is. 14.

Step-by-step explanation:

167−2=165

134−2=132

Now any of the common factors of 165 and 132 will be the required divisor

On factorization

165=3×5×11

132=2×2×3×11

Their common factors are 11 and 3=11×3=33

Hence 33 is the required divisor