Question

Q. The length of a metal rod at 0°C is 0.5m. When it is heated, its length increases by 2.7mm. The final temperature of rod is (coeff. of linear expansion of metal = 90x 104°C.

PLZZ ANYONE HELP ME IN THIS QUESTION................!!​

Answer 1

Answer:

I am considering coeff of linear expansion of metal as 90*10^(-4)/°c (linear expansion general value ranges like dat)

this is due to thermal stress due to free expansion case,

and the thermal deformation is given by,

∆T(elongation) = aplha* ∆t * L,

=> 2.7 = (90*10^(-4))*(t2-100)*500,

=> 2.7 = 0.9*(t2-100),

=> t2-100 = 3,

=> t2 = 103°c.

Hope it helps u...

Answer 2

Answer:

good morning tanveer.......

ki kar di va

ma vi vadia va