Physics, asked by learner3021, 2 months ago

Q) The position of an object moving on a straight line is given by x=t^(3)-2t^(2)-4t,where x is expressed in meter and t in second.
a) Derive the expressions for the velocity and acceleration of the object as a function of time.

Answers

Answered by upsales
3

Answer:

The position of an object moving on a straight line is defined by the relation, where x is expressed in meter and t in second. Determine <br> (a) the average velocity during the interval of 1 second to 4 second. <br> (b) the velocity at t = 1 s and t = 4 s, <br> (c) the average acceleration during the interval of 1 second to 4 second. <br> (d) the acceleration at t = 4 s and

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Answered by Anonymous
1

Answer:

the expression for velocity is v=3t²-4t-4

the expression for acceleration is a =6t-4

Explanation:

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