Question

(q) the present age of a father is 3 years more than three times the age of his son. three years hence, fathers age will. be 10 years more than twice the age of the son. find the present age of the father.

Answer 1

Father  = x

Son = y

x  = 3 + 3y

3 + x = 10 + 2y + 3

3 + 3 + 3y = 10 + 2(y + 3)

y = 10 - 6 + 6 = 10

Father's present age = 3 + 30 = 33

Answer 2

let the age of father be ' y ' and age of his son be ' x '

______________________________
Define present age :
______________________________

present age of son = x

present age of father y = 3 x + 3

______________________________
Define their age of 3 yr hence : + 3
______________________________

age of son = x + 3

age of father = 3x + 3 + 3 = 3x + 6

according to question ,
_______________________________

after 3 years , father's age will be 10 yrs more than twice the age of son .

3 x + 6 = 2 ( x + 3 ) + 10

3 x + 6 = 2 x + 6 + 10

3 x - 2 x = 16 - 6

x = 10 yr

present age of son = 10 yr

then , present age of father

3 x + 3 = 3 (10 ) + 3 = 33 yr

therefore,

present age of father = 33 yr

_______________________________
Your Answer : 33 yr
_______________________________