Q : The product of two 2 digit numbers is 1998, if the product of their unit digit is 28 and that of tens digit is 15, find the number. Please advise the calculation this is class 6th Maths question
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Step-by-step explanation:
Let the number be 10 x +y & 10 a +b
(10x +y ) (10a +b) = 1998
y * b =28
x*a = 15
100ax +10bx +by = 1998
1500 +10bx +10ay +28 = 1998
10 bx + 10ay = 1998 -28 -1500
10 bx + 10ay = 470
bx + ay = 47
possible values (4,7) and (7,4)
Other possible value (3,5) (5,3)
when x =7 , a =4
when y = 3 , b = 5
1st number = 10y +x = 37
2nd number = 10b+a = 54
product of two number 37 * 54 = 1998
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