Math, asked by AnoopWT, 5 days ago

Q. The product of two consecutive multiples of 4 is 672.
a:-write a second degree equation by taking the smaller multiples as x.
b:-find the numbers?

Answers

Answered by xyz7792
6

Answer:

The sum of two consecutive multiples of 4 is 672. What is the second degree equation by taking the first number as x?

Let the number be = x

It is multiple of 4 then it will become = 4*1*x

Next consecutive multiple of 4 will be = 4*2*x=8x

According to question sum of these consecutive multiple of 4 is equal to 672

4x + 8x =672

12x =672

x=672/12 = 56

Put the value of x in 4x and 8x

4*56=224

8*56=448

Answer 224 and 448

Step-by-step explanation:

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Answered by syedtahir20
0

Answer:

Here is required answer.

Step-by-step explanation:

As per question we have given

The product of two consecutive multiples of 4 is 672

We have to find

a:-write a second degree equation by taking the smaller multiples as x.

b:-find the numbers?

Let the number be = x

It is multiple of 4 then it will become = 4*1*x

Next consecutive multiple of 4 will be = 4*2*x=8x

According to question sum of these consecutive multiple of 4 is equal to 672

4x * 4( x+ 1) = 672

4x * ( 4x +4) = 672

16x ^2 + 16x = 672

x^2 +x = 42

Therefore the 2nd degree equation is x^2 +x -42 = 0

This equation is factorable

(x +7) * (x -6) = 0

x = -7 and x = 6

if x = -7, then the two numbers are -28 and -24

if x = 6, then the two numbers are 24 and 28

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