Question

Q. The roots of each of the following quadratics are real and equa + find k. G 34 24 ky+12=0​

Answer 1

Answer:

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P(X) = 3Y² + KY + 12 = 0

Here,

A = 3 , B = K and C = 12

The roots of the given equation is real and equal it means Discriminant of the equation is greater than 0.

D = (B)² - 4AC

D = (K)² - 4 × 3 × 12

D = (K² - 144 )

Now,

(K²-144) = 0

K² = 144

K = ✓144

K = -12 OR 12.

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