Question

Q. The short and long hands of a clock are 4cm and 6cm long respectively. Find the sum of distances travelled by their tips in 2 days.

Answer 1

The tips cover circular paths.
The hour hand covers 4 complete circles in 2 days (48 hours)
Distance = 2 x 22/7 x 4 x 4 = 100.57 cm

The minute hand covers = 48 Circles in 2 days (Each hour = 1 circle)
Distance = 2 x 22/7 x 6 x 48 = 1810.23 cm

Total distance = 100.57 + 1810.23 = 1910.8 cm

Answer 2

Solution:-
Short hand is the hour hand and it completes 1 revolution in 12 hours.
In 12 hours, distance = 2πr = 2*22/7*4
And, in 2 days or 48 hours, the distance covered = 2*4*22/7*4
= 704/7
= 100.57 cm
Long hand is the minute hand and it completes 1 revolution in 1 hour.
So, in 48 hours, it will take 48 revolutions.
= 2*22/7*6*48
= 12672/7
= 1810.285
Total distance covered by the two hands = 100.57 + 1810.285
= 1910.855 cm
Answer.