Question

Q.The sides of a triangular field at 400m,350m, and 300m respectively.In a plane of the field the greatest side measures 2.4 cm, find the length of the other sides.

Answer 1

s= 325  + 300 + 125 /2 = 375

( s-a) = (375 - 325 ) = 50
(s-b)  = (375 - 300 ) = 75 
(s-c)  = ( 375 - 125 ) = 250

√ s (50) (75) (250)

√ 375 x 937500

351562500

Answer 2

Answer:

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