Question

Q. The sum of three consecutive multiples of 11 is 363. Find these
multiples.​

Answer 1

Step-by-step explanation:

11x+11 (x+1)+11 (x+2) =363

11x+11x+11+11x+22=363

33x+33=363

33x=363-33

x=330/33

x=10

Answer 2

Answer:

110 , 121 , 132

Step-by-step explanation:

11x+11(x+1)+11(x+2) = 363

= 11x+11x+11+11x+22 = 363

= 33x+33 = 363

= 33x = 363 - 33

= 33x = 330

= x = 330÷33

= x = 10

• First multiple = 11x = 11×10=110
• Second multiple = 11(x+1) = 11(10+1) = 11×11 = 121
• Third multiple = 11(x+2) = 11×12 = 132

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