Question

Q. The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs.  110. What will a person have to pay for travelling a distance of 25 km?​

Answer 1

Answer:

Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.

According to the question,

x + 10y = 75-------(1)

x + 15y = 110--------(2)

Subtracting equation (ii) from equation (i), we get

– 5y = – 35

⟹ y = 7

Putting y = 7 in equation (i), we get x = 5

∴Total charges for travelling a distance of 25 km

=x+25

= (5 + 25 × 7)=180

Answer 2

Answer:

Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.

According to the question,

⟹ x + 10y = 75

⟹ x + 15y = 110

Subtracting equation (ii) from equation (i), we get

⟹ – 5y = – 35

⟹ y = 7

Putting y = 7 in equation (i), we get x = 5

∴ Total charges for travelling a distance of 25 km = x + 25y

= (5 + 25 × 7)

= (5 + 175)

= Rs. 180