Q. The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110. What will a person have to pay for travelling a distance of 25 km?
Answers
Answer:
Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.
According to the question,
x + 10y = 75-------(1)
x + 15y = 110---------(2)
Subtracting equation (ii) from equation (i), we get
– 5y = – 35
⟹ y = 7
Putting y = 7 in equation (i), we get x = 5
∴Total charges for travelling a distance of 25 km
= x+ 25y
=(5 + 25 × 7)=Rs 180
Answer:
Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.
According to the question,
⟹ x + 10y = 75
⟹ x + 15y = 110
Subtracting equation (ii) from equation (i), we get
⟹ – 5y = – 35
⟹ y = 7
Putting y = 7 in equation (i), we get x = 5
∴ Total charges for travelling a distance of 25 km = x + 25y
= (5 + 25 × 7)
= (5 + 175)
= Rs. 180