Q. The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110. What will a person have to pay for travelling a distance of 25 km?
Answers
Answered by
3
Answer:
Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.
According to the question,
x + 10y = 75-------(1)
x + 15y = 110--------(2)
Subtracting equation (ii) from equation (i), we get
– 5y = – 35
⟹ y = 7
Putting y = 7 in equation (i), we get x = 5
∴Total charges for travelling a distance of 25 km
=x+25
= (5 + 25 × 7)=180
Answered by
0
Step-by-step explanation:
Let the fixed charges be x and charge per km be y.
ATQ,
x+10y = 75 —1
x+ 15y =110—2
Subtract 1 from 2
5y =35
y=7
Put y=7 in 1
x+10*7=75
x+70=75
x=5
So, the fixed charges are Rs. 5 and charges per km are Rs. 7 per km
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