Math, asked by lolwa6, 11 months ago

Q. The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110. What will a person have to pay for travelling a distance of 25 km?​

Answers

Answered by ItzLava90
3

Answer:

Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.

According to the question,

x + 10y = 75-------(1)

x + 15y = 110--------(2)

Subtracting equation (ii) from equation (i), we get

– 5y = – 35

⟹ y = 7

Putting y = 7 in equation (i), we get x = 5

∴Total charges for travelling a distance of 25 km

=x+25

= (5 + 25 × 7)=180

Answered by sir82
0

Step-by-step explanation:

Let the fixed charges be x and charge per km be y.

ATQ,

x+10y = 75 —1

x+ 15y =110—2

Subtract 1 from 2

5y =35

y=7

Put y=7 in 1

x+10*7=75

x+70=75

x=5

So, the fixed charges are Rs. 5 and charges per km are Rs. 7 per km

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