Q. The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110. What will a person have to pay for travelling a distance of 25 km?
Answers
Answer:
Answer:
Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.
According to the question,
x + 10y = 75-------(1)
x + 15y = 110--------(2)
Subtracting equation (ii) from equation (i), we get
– 5y = – 35
⟹ y = 7
Putting y = 7 in equation (i), we get x = 5
∴Total charges for travelling a distance of 25 km
=x+25
= (5 + 25 × 7)=180
Answer:
THE FIXED CHARGE IS RUPEES 5 AND CHARGE PER KM IS RUPEES 7
Step-by-step explanation:
LET THE FIXED CHARGE BE X AND CHARGE PER KM BE Y
AS PER QUES
CASE 1 X+10Y=75 EQ 1
CASE 2 X+ 15Y =115 EQ2
SOLVING 1 AND 2 EQUATIONS BY ELIMINATION METHOD
X+10Y=75
X+15Y=115
- - -
-5Y= -35
Y =7 PUT IN EQUATION 1
X + 10(7)=75
X=5
FOR TRAVELLING 25 KM CHARGE WILL BE
X+25Y
5+25(7)
5+175
180