Question

Q. The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110. What will a person have to pay for travelling a distance of 25 km?​

Answer 1

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Sol.

Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.

According to the question,

x + 10y = 75

x + 15y = 110

Subtracting equation (ii) from equation (i), we get

– 5y = – 35

⟹ y = 7

Putting y = 7 in equation (i), we get x = 5

∴Total charges for travelling a distance of 25 km = x + 25y

= (5 + 25 × 7)

= (5 + 175)

= Rs 180

Answer 2

Answer:

From 10km to 15km, 5km is travelled

Additional charge for 15km journey = ₹110 - ₹75 = ₹35

Thus , charge per km = ₹35 ÷ 5 = ₹7

Now, for 10km, expected charge = ₹7 × 10 = ₹70

Thus, fixed charge = ₹75 - ₹70 = ₹5

Finally, charge of 25km journey = ₹7×25 + ₹5 = ₹180

Hope it helps ☺️

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