Q) The value of ^G* for the phosphorylation of glucose in glycolysis is 13.8kJ/mol . Find the value of Kc at 298K?
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ΔG°=-2.303RT log Kc
Where R=8.314JK^-1;T=298k;
Given,
ΔG°=13.8KJ/mol but as value of R is in Joules we take it as 13.8×10^3j/mol
Therefore 13.8×10^3=-2.303×8.314×298log Kc
log Kc=-2.4185
Taking antilog
Kc=0.2621×10^-2
Where R=8.314JK^-1;T=298k;
Given,
ΔG°=13.8KJ/mol but as value of R is in Joules we take it as 13.8×10^3j/mol
Therefore 13.8×10^3=-2.303×8.314×298log Kc
log Kc=-2.4185
Taking antilog
Kc=0.2621×10^-2
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