Physics, asked by GabbarSingh6479, 1 year ago

Q) the wavelength of light beam a is twice the wavelength of light beam

b. the energy of a photon in beam a is ?

Answers

Answered by ChetanRA
4
We have the relation E = hc / λ
Thus, energy of the photon is inversely proportional to wavelength of the light beam.

Let the wavelength of light beam 'a' be λ1 and that of 'b' be λ2.
It is given in the data that λ1 = 2 λ2

From the relation between E and λ mentioned above, we can say that

 \frac{E1}{E2}  = λ2 / λ1 

\frac{E1}{E2} = λ2 / 2 λ2 (as  λ1 = 2 λ2)

\frac{E1}{E2} = \frac{1}{2}

E2 = 2 E1

E1 = E2 / 2

Thus, energy of a photon in beam 'a' is half that of a photon in beam 'b'.
 
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