Question

Q
The wire of length I is cut into 2 parts & its fundmental
frequency of vibration were 200 Hz & 300 Hz What will be
the initial length I if speed of wave in wire is 330 m/s​

Answer 1

Explanation:

Let the initial length of the wire be l metres.

It is divided into two parts with lengths l1 and l2 meters.

Now, for the 1st wire,

velocity of the wave = frequency of the wave / wavelength

thus, 330 m/s = 200 Hz * l1 metre

or, l1 = 330/220 m = 3/2 m

For the 2nd wire,

330 m/s = 300 Hz * l2 metre

or, l2 = 330/300 m = 11/10 m

Therefore, the initial length of the wire = l1 + l2 = 3/2 + 11/10 metres = 1.50 + 1.1 = 1.6 metres