Question

Q.
There are 3 red and 4 white balls in a box. Four balls are selected at random with replacement
from the box. Find the probability of the event of getting (i) 2 red balls and 2 white balls
(ii) all four white balls among the selected balls using binomial distribution.​

Answer 1

Anwer :

cases of drawing same colour are selecting 3 from 3 black balls and selecting 3 from 4 white balls

=

3

C

3

+

4

C

3

=5

total number of cases =

9

C

3

=84

therefore probability of drawing 3 balls of same colour is

84

5