Q. Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma , Salma to Mandip , Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6m each, what is the distance between Reshma and Mandip ?
NCERT Mathematics
Class 9th
Ch 10 (Circles)
Exercise 10.4
Question no. 5
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Answer:
9.6m is the answer.
EXPLANATION :
Draw perpendicular OA and OB on RS and SM respectively.
Let R,S and M be the position of Reshma, Salma and Mandip respectively.
AR= AS=
2
6
= 3 cm
OR= OS= OM= 5 m [radii of circle]
In △OAR
OA
2
+ AR
2
= OR
2
OA
2
+
3 2
5 2
OA=
25−9
OA= 4 m
We know that in an isosceles triangle altitude divides the base ,
So, in △RSM
∠RCS= 90
o
RC=CM
Area of
△ORS=
2
1
×
OA×
RS
2
1
× RC× OS=
2
1
× 4× 6
RC× 5= 24
RC= 4.8 m
RM= 2RC= 2× 4.8= 9.6 m
So, distance between Reshma and Mandip is
9.6 m
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