Question

Q)Three moles of an ideal gas kept at a constant
temperature of 300 K are compressed from a
volume of 4 litre to 1 litre. Calculate the work
done in the process. (R-8.31 ) mol K-)​

Answer 1

Answer:

Work done in an isothermal process is given by

W=2.3026nRTlog

10

V

1

V

2

Here, n=3,R=8.31J/mol

o

C

T=300K, V

1

=4L, V

2

=1L

Hence, W=2.3026×3×8.31×300×log

10

4

1

= 17221.15(−2log

10

2)

= −17221.15×2×0.3010=−10368J