Question

Q Three natural numbers x,y,z leave remaiders 18,21,20 respectively divided by 23. Find the remainder when x+y+z is divided by 23.

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Answer 1

Hope u will understand.

Answer 2

Answer:

13

Step-by-step explanation:

remainders are 18 ,21 ,20 if divided by 23

number = quotient × divisor + remainder

let quotient =1

than numbers x= 23+18=41

y= 23+21= 44

z= 23+20 = 43

sum of numbers = 41+44+43 = 128

128/23= 13 remainder

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