Q. Three of the exterior angles of an n-sided polygon are 50 each, two of its interior angles are 127 and 135 and the remaining interior angles are 173 each. Find the value of n
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We know that the sum of the exterior angles of any polygon is always 360 degrees.
Two other exterior angles are 180–127 or 53º and 180–135 or 45º.
Therefore the sum of the 5 exterior angles is 150+53+45 = 248º.
The sum of the remaining exterior angles = 360–248 or 112º
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